v belts

[jonnydot]

would a 10 mm width v belt be strong enough for a 2300 watt motor (approx 3hp)?

[rossbotics]

Depends on how much torque your putting on it, what are you driving with it?

Doug

[jonnydot]

I purchased this unit for the motor https://www.ebay.com.au/itm/Giantz-2...53.m2749.l2649

[jonnydot]

I don't know the rpm so I cannot work out the torque

[rossbotics]

Ok, then what are you planning to do with it? make a grinder ? Etc.

Doug

[jonnydot]

Ok, then what are you planning to do with it? make a grinder ? Etc.

Doug

Oscillating spindle sander https://www.dropbox.com/s/nh359qla57...ander.pdf?dl=0

[Frank S]

Like Doug said a lot depends on the application, plus the driving pulley diameter sped reduction ratio IE the driven pulley diameter divided by the driving pulley center distances will it be a continuous load drawing full rated wattage or varying loads.
If your loading is intermittent rarely requiring full power and the small pulley is the driving pulley at least 7 times in diameter of the width of the belt then
the short answer would be probably, but in general the short answer would be not quite.
And if the driving pulley diameter is to be less than 7 times the width of the belt or the driven pulley is smaller than the driving then the short answer would be no
These belt selection guides may help you out
https://www.baldor.com/mvc/DownloadCenter/Files/MS4050
https://www.allworldmachinery.com/im...DESIGN_MAN.pdf

[Frank S]

Ok, your sander is going to have yet another factor that comes into play unless the shaft is going to be splined so you can allow the shaft to travel freely up and down without the pulley moving, you are going to have to run your belt slightly loose due to the vertical movement of the shaft the sanding drum will be mounted on plus you will most likely want the drum spinning faster than the motor unless the motor RPM is at least 3600 RPM.
This will mean you will want a reasonably long center distance. the 2 guides I previously posted should have a section for maximum allowable pulley misalignment angle. you will need to factor that equation into your power factor equation.
However in your machine design the limiting factor is not going to be the design hp of the belt but the shaft diameter. with the 20 mm shaft you could get away with a 500 to 1500 watt motor. Since you may already have the 2300 watt motor I'd say run with it just be sure that the pulley on the shaft is between 2 bearings located as near as possible to both vertical limits of the shaft movement even if you have to add a 3rd bearing

[milomilo]

I think you need at the least a 5/8" wide belt.

[Toolmaker51]

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