Andyt (Sep 8, 2018), Jon (Mar 21, 2016), jrocasio (Dec 3, 2016), kbalch (Mar 21, 2016), Lee Bell (Sep 7, 2018), Paul Jones (Mar 21, 2016), PJs (Mar 24, 2016), Raytonian (Mar 19, 2019), rlm98253 (Dec 21, 2017), robbitalia18 (Aug 4, 2024), scoopydo (Mar 24, 2016), Scotsman Hosie (May 25, 2018), Toolmaker51 (Dec 24, 2017), trevor_60_r (Nov 3, 2024), tuchie (Dec 23, 2023), werdegast (May 7, 2021)
Thanks Captainleeward! We've added your Circle Center Finder to our Measuring and Marking category, as well as to your builder page: Captainleeward's Homemade Tools. Your receipt:
I've a pile of 1" x 8" steel disk's to center drill, making machine leveling pads. Commercial machinist center heads don't range beyond 5'' diameter ~...
So make one!
This will be great. Beats loading them up and chucking in lathe at work.
Sincerely,
Toolmaker51
...we'll learn more by wandering than searching...
This is probably a good place to mention the mathematical background of center finders.
There's a provable theorem from geometry that says:
The perpendicular divisor of the chord of a circle passes through the center of the circle.
When you use a center head, the two tangent points where the head touches the circular object define a chord on that circle. The blade is mechanically set to bisect the angle between the arms of the head so it automatically provides the perpendicular bisector of the chord. When two of these chord bisectors are drawn, the point where they cross must be the center.
The technique is extendable to circles or circular segments too large for any sort of hand-held tool. Simply draw two chords (as nearly perpendicular as possible), construct their bisectors and the point where they cross is the center. Surveyors employ this technique, using their transits to establish the perpendicular bisectors.
The diameter of a circle is a chord itself. Thus its perpendicular bisector must pass through the diameter at the center of the circle.
It should also be apparent that this math insight can be used to construct a circle that passes through any three non-colinear points. Construct two chords using the three points. The center of the circle is then the point where their bisectors cross and the radius is the distance from the center to any of the points.
---
Regards, Marv
Failure is just success in progress
That looks about right - Mediocrates
The intended application suggests you don't need tenths (or even thousandths) accuracy in locating the center so perhaps a device based on my math post above might work.
On a metal bar, mount two identical pins about six inches apart on the centerline of the bar. Draw a line on the bar midway between the two pin locations. This is your "chord generator".
Push it against the circumference of the disk until the pins touch. Lay a machinist square on the top of the bar, align with the center mark and draw the bisector on the disk. Repeat. The center is the point where the two lines cross.
It's just a gedanken-design but it might inspire you in your build.
---
Regards, Marv
Failure is just success in progress
That looks about right - Mediocrates
There are currently 1 users browsing this thread. (0 members and 1 guests)
Bookmarks